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JEE Mains · Physics · STD 11 - 5. work,energy,power and collision
Two particles, of masses \(M\) and \(2M\), moving as shown, with speeds of \(10\, m/s\) and \(5\, m/s\), collide elastically at the origin. After the collision, they move along the indicated directions with speeds \(v_1\) and \(v_2\) respectively. The value of \(v_1\) and \(v_2\) are nearly
- A \(3.2\, m/s\) and \(12.6\, m/s\)
- B \(6.5\, m/s\) and \(6.3\, m/s\)
- C \(6.5\, m/s\) and \(3.2\, m/s\)
- D \(3.2\, m/s\) and \(6.3\, m/s\)
Answer & Solution
Correct Answer
(B) \(6.5\, m/s\) and \(6.3\, m/s\)
Step-by-step Solution
Detailed explanation
\begin{array}{l} 2MV,\cos {30^ \circ } + M{v_2}\cos {45^ \circ }\\ = 10\,M\,\cos {30^ \circ } + 10\cos {45^ \circ }\\ \Rightarrow {v_1}\sqrt 3 + \frac{{{v_2}}}{{\sqrt 2 }} = 5\sqrt 3 + 5\sqrt 2 \,\,\,\,\,\,\,\,\,\,\,...\left( i \right)\\ 2MV,\,\sin {30^ \circ } - M{V_2}\sin {45^…
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