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JEE Mains · Physics · STD 12 - Electric charges and fields
  • JEE Mains 2024
  • Hard
  • Numerical

An electric field \(\overrightarrow{\mathrm{E}}=(2 \mathrm{xi}) \mathrm{NC}^{-1}\) exists in space. \(\mathrm{A}\) cube of side \(2 \mathrm{~m}\) is placed in the space as per figure given below. The electric flux through the cube is _______ \(\mathrm{Nm}^2 / \mathrm{C}\)

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Answer & Solution

Correct Answer

(D) \(16\)

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Detailed explanation

\(\overrightarrow{\mathrm{E}}=2 x \hat{\mathrm{i}}\)
\(\phi=\overrightarrow{\mathrm{E}} \cdot \overrightarrow{\mathrm{A}}\)
\(\phi_{\text {in }}=-4 \times 4=-16 \mathrm{Nm}^2 / \mathrm{c}\)
\(\phi_{\text {out }}=8 \times 4=32 \mathrm{Nm}^2 / \mathrm{c}\)
\(d_{\text {net }}=\phi_{\text {in }} \phi_{\text {out }}=-16+32=16 \mathrm{Nm}^2\)
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