JEE Mains · Physics · STD 12 - 1. Electric charges and fields
An electric field \(\overrightarrow{\mathrm{E}}=(2 \mathrm{xi}) \mathrm{NC}^{-1}\) exists in space. \(\mathrm{A}\) cube of side \(2 \mathrm{~m}\) is placed in the space as per figure given below. The electric flux through the cube is _______ \(\mathrm{Nm}^2 / \mathrm{C}\)
- A \(13\)
- B \(14\)
- C \(15\)
- D \(16\)
Answer & Solution
Correct Answer
(D) \(16\)
Step-by-step Solution
Detailed explanation
\(\overrightarrow{\mathrm{E}}=2 x \hat{\mathrm{i}}\) \(\phi=\overrightarrow{\mathrm{E}} \cdot \overrightarrow{\mathrm{A}}\) \(\phi_{\text {in }}=-4 \times 4=-16 \mathrm{Nm}^2 / \mathrm{c}\) \(\phi_{\text {out }}=8 \times 4=32 \mathrm{Nm}^2 / \mathrm{c}\)…
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