JEE Mains · Physics · STD 11 - 10.1, thermonetry,thermal expansion and calorimetry
The height of victoria falls is \(63\, {m}\). What is the difference in temperature of water at the top and at the bottom of fall ? (In \(^{\circ} {C}\)) [Given \(1\, {cal}=4.2\, {J}\) and specific heat of water \(\left.=1 \,{cal} \,{g}^{-1}\;{ }^{\circ}\, {C}^{-1}\right]\)
- A \(0.147\)
- B \(14.76\)
- C \(1.476\)
- D \(0.014\)
Answer & Solution
Correct Answer
(A) \(0.147\)
Step-by-step Solution
Detailed explanation
Change in \(P.E.\) \(=\) Heat energy \({mgh}={mS} \Delta {T}\) \(\Delta {T} =\frac{g h}{S}\) \(=\frac{10 \times 63}{4200\, {J} / {kgC}}\) \(=0.147^{\circ} {C}\)
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