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JEE Mains · Physics · STD 11 - System of particles and rotational motion
  • JEE Mains 2024
  • Hard
  • MCQ

A particle of mass \(m\) projected with a velocity ' \(u\) ' making an angle of \(30^{\circ}\) with the horizontal. The magnitude of angular momentum of the projectile about the point of projection when the particle is at its maximum height \(\mathrm{h}\) is _______.

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Answer & Solution

Correct Answer

(A) \(\frac{\sqrt{3}}{16} \frac{\mathrm{mu}^3}{\mathrm{~g}}\)

Step-by-step Solution

Detailed explanation

\( \mathrm{L}=m u \cos \theta H \)

\( =m u \cos \theta \times \frac{u^2 \sin ^2 \theta}{2 g} \)

\( =\frac{m u^3}{2 g} \times \frac{\sqrt{3}}{2} \times\left(\frac{1}{2}\right)^2=\frac{\sqrt{3} m u^3}{16 g}\)

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