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JEE Mains · Physics · STD 12 - Current electricity
  • JEE Mains 2019
  • Medium
  • MCQ

A cell of internal resistance \(r\) drives current through an external resistance \(R\) . The power delivered by the cell to the external resistance will be maximum when:

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Answer & Solution

Correct Answer

(D) \(R = r\)

Step-by-step Solution

Detailed explanation

Current \(i=\frac{E}{r+R}\)

Power generated in \(R\)

\(P=i^{2} R\)

\(P=\frac{E^{2} R}{(r+R)^{2}}\)

For maximum power \(\frac{\mathrm{dP}}{\mathrm{dR}}=0\)

\(E^{2}\left[\frac{(r+R)^{2} \times 1-R \times 2(r+R)}{(r+R)^{4}}\right]=0\)

\(\Rightarrow r=R\)

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