JEE Mains · Physics · STD 12 - Current electricity
- JEE Mains 2019
- Medium
- MCQ
A cell of internal resistance \(r\) drives current through an external resistance \(R\) . The power delivered by the cell to the external resistance will be maximum when:
Pick an option to check your answer.
Answer & Solution
Correct Answer
(D) \(R = r\)
Step-by-step Solution
Detailed explanation
Current \(i=\frac{E}{r+R}\)
Power generated in \(R\)
\(P=i^{2} R\)
\(P=\frac{E^{2} R}{(r+R)^{2}}\)
For maximum power \(\frac{\mathrm{dP}}{\mathrm{dR}}=0\)
\(E^{2}\left[\frac{(r+R)^{2} \times 1-R \times 2(r+R)}{(r+R)^{4}}\right]=0\)
\(\Rightarrow r=R\)
More questions from Physics
- A cyclotron is used to accelerate protons. If the operating magnetic field is \(1.0\,T\) and the radius of the cyclotron 'dees' is \(60 cm\), the kinetic energy of the accelerated protons in \(MeV\) will be. [use \(m _{p}=1.6 \times 10^{-27} kg , e =1.6 \times 10^{-19} C\) ]JEE Mains 2022 Medium
- Steel ruptures when a shear of \(3 .5 \times 10^8\,\,N\,m^{-2}\) is applied. The force needed to punch a \(1\,cm\) diameter hole in a steel sheet \(0.3\,cm\) thick is nearlyJEE Mains 2014 Medium
- A resistor develops \(300 \,J\) of thermal energy in \(15 \,s\), when a current of \(2\, A\) is passed through it. If the current increases to \(3 \,A\), the energy developed in \(10\,\,s\) is........\(J.\)JEE Mains 2022 Medium
- If frequency of electromagnetic wave is \(60 \mathrm{MHz}\) and it travels in air along \(\mathrm{z}\) direction then the corresponding electric and magnetic field vectors will be mutually perpendicular to each other and the wavelength of the wave (in \(\mathrm{m}\) ) is _______.JEE Mains 2024 Hard
- Two concentric circular coils with radii \(1\,cm\) and \(1000\,cm\), and number of turns \(10\) and \(200\) respectively are placed coaxially with centers coinciding. The mutual inductance of this arrangement will be \(.........\times 10^{-8}\,H\)(Take, \(\pi^2=10\))JEE Mains 2023 Hard
- Given below are two statement Statement \(-I\) : What \(\mu\) amount of an ideal gas undergoes adiabatic change from state \(\left( P _{1}, V _{1}, T _{1}\right)\) to state \(\left( P _{2}, V _{2}, T _{2}\right)\), the work done is \(W =\frac{1 R \left( T _{2}- T _{1}\right)}{1-\gamma}\), where \(\gamma=\frac{ C _{ P }}{ C _{ V }}\) and \(R =\) universal gas constant, Statement \(-II\) : In the above case. when work is done on the gas. the temperature of the gas would rise. Choose the correct answer from the options given belowJEE Mains 2022 Medium
More PYQs from JEE Mains
- A liquid column of height \(0.04 \mathrm{~cm}\) balances excess pressure of soap bubble of certain radius. If density of liquid is \(8 \times 10^3 \mathrm{~kg} \mathrm{~m}^{-3}\) and surface tension of soap solution is \(0.28 \mathrm{Nm}^{-1}\), then diameter of the soap bubble is _______ \(\mathrm{cm}\). \(\text { (if } g=10 \mathrm{~ms}^{-2} \text { ) }\)JEE Mains 2024 Hard
- The magnetic field at the center of current carrying circular loop is \(B _{1}\). The magnetic field at a distance of \(\sqrt{3}\) times radius of the given circular loop from the center on its axis is \(B_{2}\). The value of \(B_{1} / B_{2}\) will be.JEE Mains 2022 Medium
- The escape velocity of a body on a planet \('A'\) is \(12 \,kms ^{-1}\). The escape velocity of the body on another planet \('B'\) , whose density is four times and radius is half of the planet \('A'\), is ................... \(kms ^{-1}\)JEE Mains 2022 Medium
- Two short bar magnets oflength \(1\ cm\) each have magnetic moments \(1.20\ Am^2\) and \(1.00\ Am^2\) respectively. They are placed on a horizontal table parallel to each other with their \(N\) poles pointing towards the South. They have a common magnetic equator and are separated by a distance of \(20.0\ cm\). The value of the resultand horizontal magnetic induction at the mid-point \(O\) of the line joining their centres is close to (Horizontal component of earth.s magnetic induction is \(3.6 \times 10^{-5}\) \(Wbm^{-2}\) )JEE Mains 2013 Hard
- A source of potential difference \(V\) is connected to the combination of two identical capacitors as shown in the figure. When key ' \(K\) ' is closed, the total energy stored across the combination is \(E _{1}\). Now key ' \(K\) ' is opened and dielectric of dielectric constant 5 is introduced between the plates of the capacitors. The total energy stored across the combination is now \(E _{2}\). The ratio \(E _{1} / E _{2}\) will be :
JEE Mains 2022 Hard