JEE Mains · Physics · STD 11 - Waves and sound
- JEE Mains 2023
- Easy
- Numerical
The equation of wave is given by \(Y=10^{-2} \sin 2 \pi\left(160 t-0.5 x+\frac{\pi}{4}\right)\) Where \(x\) and \(Y\) are in \(m\) and \(t\) in \(s\). The speed of the wave is \(.....\,km h ^{-1}\)
Pick an option to check your answer.
Answer & Solution
Correct Answer
(B) \(1152\)
Step-by-step Solution
Detailed explanation
\(V =\frac{\omega}{ k }=\frac{2 \pi \times 60}{2 \pi \times 0.5}=\frac{160}{0.5}\,m / s\)
\(=\frac{160}{0.5} \times \frac{18}{5}\,km / h\)
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