JEE Mains · Physics · STD 12 - Moving charges and magnetism
- JEE Mains 2026
- Easy
- MCQ
A current carrying is placed vertically and a particle of mass m with charge Q is released from rest. The particle moves along the axis of solenoid. If \(g\) is acceleration due to gravity then the acceleration (a) of the charged particle will satisfy :
Pick an option to check your answer.
Answer & Solution
Correct Answer
(A) \( a = g \)
Step-by-step Solution
Detailed explanation
Since the solenoid is placed vertically, the magnetic field inside the solenoid will be either along - y or + y axis.
⇒ Particle will gain velocity along -y axis.
\(\Rightarrow \quad \overrightarrow{ F }_{ B }= q (\overrightarrow{ v } \times \overrightarrow{ B })\)
\(\Rightarrow \quad \overrightarrow{ F }_{ B }=0\)
\(\Rightarrow \quad \overrightarrow{ F }_{\text {net }}= mg\)
\(\Rightarrow \quad a _{\text {net }}= g\)
⇒ Particle will gain velocity along -y axis.
\(\Rightarrow \quad \overrightarrow{ F }_{ B }= q (\overrightarrow{ v } \times \overrightarrow{ B })\)
\(\Rightarrow \quad \overrightarrow{ F }_{ B }=0\)
\(\Rightarrow \quad \overrightarrow{ F }_{\text {net }}= mg\)
\(\Rightarrow \quad a _{\text {net }}= g\)
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