JEE Mains · Physics · STD 12 - 3. current electricity
Different combination of \(3\) resistors of equal resistance \(R\) are shown in the figures.
The increasing order for power dissipation is:
- A \(P _{ A } < P _{ B } < P _{ C } < P _{ D }\)
- B \(P _{ C } < P _{ D } < P _{ A } < P _{ B }\)
- C \(P _{ B } < P _{ C } < P _{ D } < P _{ A }\)
- D \(P _{ C } < P _{ B } < P _{ A } < P _{ D }\)
Answer & Solution
Correct Answer
(D) \(P _{ C } < P _{ B } < P _{ A } < P _{ D }\)
Step-by-step Solution
Detailed explanation
\(P = I ^2 R\) \(R _1=\frac{3 R }{2}, R _2=\frac{2 R }{3}, R _3=\frac{ R }{3}, R _4=3 R\) Since \(i\) is same, hence \(P \alpha R\) so options \((4)\) is correct
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