JEE Mains · Physics · STD 11 - 7. gravitation
A satellite revolving around a planet in stationary orbit has time period 6 hours. The mass of planet is one-fourth the mass of earth. The radius orbit of planet is _______. (Given \(=\) Radius of geo-stationary orbit for earth is \(4.2 \times 10^4 \mathrm{~km}\) )
- A \(1.4 \times 10^4 \mathrm{~km}\)
- B \(8.4 \times 10^4 \mathrm{~km}\)
- C \(1.68 \times 10^5 \mathrm{~km}\)
- D \(1.05 \times 10^4 \mathrm{~km}\)
Answer & Solution
Correct Answer
(D) \(1.05 \times 10^4 \mathrm{~km}\)
Step-by-step Solution
Detailed explanation
\(\mathrm{T}=\frac{2 \pi \mathrm{r}^{3 / 2}}{\sqrt{\mathrm{GM}}}\) \(\frac{\mathrm{T}_1}{\mathrm{~T}_2}=\left(\frac{\mathrm{r}_1}{\mathrm{r}_2}\right)^{3 / 2}\left(\frac{\mathrm{M}_2}{\mathrm{M}_1}\right)^{1 / 2}\)…
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