JEE Mains · Physics · STD 11 - 14. waves and sound
The equation of a transverse wave travelling along a string is \(y(x, t)=4.0 \sin \left[20 \times 10^{-3} x+600 t\right] \mathrm{mm}\), where \(x\) is in mm and \(t\) is in second. The velocity of the wave is :
- A \(-60 \mathrm{~m} / \mathrm{s}\)
- B \(-30 \mathrm{~m} / \mathrm{s}\)
- C \(+30 \mathrm{~m} / \mathrm{s}\)
- D \(+60 \mathrm{~m} / \mathrm{s}\)
Answer & Solution
Correct Answer
(B) \(-30 \mathrm{~m} / \mathrm{s}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & k=20 \times 10^{-3} \mathrm{~mm}^{-1}=20 \mathrm{~m}^{-1} \\ & w=600 \mathrm{~s}^{-1} \\ & v=\frac{W}{k}=\frac{600}{20}=30 \mathrm{~m} / \mathrm{s} \end{aligned}\) and \(x \& t\) carry same sign Therefore \(\mathrm{v}=-30 \mathrm{~m} / \mathrm{s}\)
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