ExamBro
ExamBro
JEE Mains · Physics · STD 12 -Electromagnetic induction
  • JEE Mains 2022
  • Medium
  • MCQ

The magnetic flux through a coil perpendicular to its plane is varying according to the relation \(\phi=\) \(\left(5 t^{3}+4 t^2+2 t-5\right) \; Weber\). If the resistant of the coil is \(5 \; ohm\), then the induced current through the coil at \(t =2 \; sec\) will be \(....\,A\)

Pick an option to check your answer.
Verified Solution

Answer & Solution

Correct Answer

(A) \(15.6\)

Step-by-step Solution

Detailed explanation

\(\phi=5 t ^{3}+4 t ^{2}+2 t -5\)

\(|e|=\frac{d \phi}{d t}=15 t^{2}+8 t+2\)

At \(t=2,|e|=15 \times 2^{2}+8 \times 2+2\)

\(\Rightarrow e =78 \; V \Rightarrow I =\frac{ e }{ R }=\frac{78}{5}=15.60\)

From JEE Mains
Explore more questions on app