JEE Mains · Physics · STD 11 - Waves and sound
- JEE Mains 2025
- Easy
- MCQ
The equation of a wave travelling on a string is \(\mathrm{y}=\sin [20 \pi \mathrm{x}+10 \pi \mathrm{t}]\), where x and t are distance and time in SI units. The minimum distance between two points having the same oscillating speed is :
Pick an option to check your answer.
Answer & Solution
Correct Answer
(A) 5.0 cm
Step-by-step Solution
Detailed explanation
Minimum distance between 2 points having same speed is \(\frac{\lambda}{2}\).
\(\lambda=\frac{2 \pi}{\mathrm{k}}=\frac{1}{10} \mathrm{~m}=10 \mathrm{~cm}\)
\(\text { Distance }=\frac{\lambda}{2}=5 \mathrm{~cm}\)
\(\lambda=\frac{2 \pi}{\mathrm{k}}=\frac{1}{10} \mathrm{~m}=10 \mathrm{~cm}\)
\(\text { Distance }=\frac{\lambda}{2}=5 \mathrm{~cm}\)
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