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JEE Mains · Physics · STD 11 - Waves and sound
  • JEE Mains 2026
  • Easy
  • MCQ

The equation of a plane progressive wave is given by \(y = 5\cos\pi\left(200t - \dfrac{x}{150}\right)\) where \(x\) and \(y\) are in cm and \(t\) is in second. The velocity of the wave is _______ m/s.

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Verified Solution

Answer & Solution

Correct Answer

(D) \(300\)

Step-by-step Solution

Detailed explanation

The given equation of the wave is \(y = 5\cos\pi\left(200t - \dfrac{x}{150}\right)\)

Rewriting the equation, we get \(y = 5\cos\left(200\pi t - \dfrac{\pi x}{150}\right)\)

Comparing this with the standard wave equation \(y = A\cos(\omega t - kx)\), we have:

\(\omega = 200\pi\) rad/s

\(k = \dfrac{\pi}{150}\) rad/cm

The velocity of the wave is given by \(v = \dfrac{\omega}{k}\)

\(v = \dfrac{200\pi}{\dfrac{\pi}{150}} = 30000\) cm/s

Converting to m/s, we get \(v = \dfrac{30000}{100} = 300\) m/s

Answer: \(300\)
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