JEE Mains · Physics · STD 11 - Waves and sound
- JEE Mains 2026
- Easy
- MCQ
The equation of a plane progressive wave is given by \(y = 5\cos\pi\left(200t - \dfrac{x}{150}\right)\) where \(x\) and \(y\) are in cm and \(t\) is in second. The velocity of the wave is _______ m/s.
Pick an option to check your answer.
Answer & Solution
Correct Answer
(D) \(300\)
Step-by-step Solution
Detailed explanation
The given equation of the wave is \(y = 5\cos\pi\left(200t - \dfrac{x}{150}\right)\)
Rewriting the equation, we get \(y = 5\cos\left(200\pi t - \dfrac{\pi x}{150}\right)\)
Comparing this with the standard wave equation \(y = A\cos(\omega t - kx)\), we have:
\(\omega = 200\pi\) rad/s
\(k = \dfrac{\pi}{150}\) rad/cm
The velocity of the wave is given by \(v = \dfrac{\omega}{k}\)
\(v = \dfrac{200\pi}{\dfrac{\pi}{150}} = 30000\) cm/s
Converting to m/s, we get \(v = \dfrac{30000}{100} = 300\) m/s
Answer: \(300\)
Rewriting the equation, we get \(y = 5\cos\left(200\pi t - \dfrac{\pi x}{150}\right)\)
Comparing this with the standard wave equation \(y = A\cos(\omega t - kx)\), we have:
\(\omega = 200\pi\) rad/s
\(k = \dfrac{\pi}{150}\) rad/cm
The velocity of the wave is given by \(v = \dfrac{\omega}{k}\)
\(v = \dfrac{200\pi}{\dfrac{\pi}{150}} = 30000\) cm/s
Converting to m/s, we get \(v = \dfrac{30000}{100} = 300\) m/s
Answer: \(300\)
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