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JEE Mains · Physics · STD 12 - Electric potential and capacitance
  • JEE Mains 2017
  • Hard
  • Numerical

The energy stored in the electric field produced by a metal sphere is \(4.5\, J\). lf the sphere contains \(4\,\mu C\) charge, its radius will be.......\(mm\) : [Take : \(\frac{1}{{4\pi {\varepsilon _0}}} = 9 \times {10^9}\,N - {m^2}\,/{C^2}\, ]\)

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Answer & Solution

Correct Answer

(D) \(16\)

Step-by-step Solution

Detailed explanation

Energy of sphere \(=\frac{Q^{2}}{2 C}\)

\(4.5=\frac{16 \times 10^{-12}}{2 C}\)

\(C=\frac{16 \times 10^{-12}}{9}=4 \pi \varepsilon_{0} R\)

(capacity of spherical conductor)

\(\mathrm{R}=\frac{16 \times 10^{-12}}{9} \times \frac{1}{4 \pi \varepsilon_{0}}\)

\(\because \frac{1}{4 \pi \varepsilon_{0}}=9 \times 10^{9}\)

\(=9 \times 10^{9} \times \frac{16}{9} \times 10^{-12}=16\, \mathrm{mm}\)

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