JEE Mains · Physics · STD 12 - 2. Electric potential and capacitance
The energy stored in the electric field produced by a metal sphere is \(4.5\, J\). lf the sphere contains \(4\,\mu C\) charge, its radius will be.......\(mm\) : [Take : \(\frac{1}{{4\pi {\varepsilon _0}}} = 9 \times {10^9}\,N - {m^2}\,/{C^2}\, ]\)
- A \(20\)
- B \(32\)
- C \(28\)
- D \(16\)
Answer & Solution
Correct Answer
(D) \(16\)
Step-by-step Solution
Detailed explanation
Energy of sphere \(=\frac{Q^{2}}{2 C}\) \(4.5=\frac{16 \times 10^{-12}}{2 C}\) \(C=\frac{16 \times 10^{-12}}{9}=4 \pi \varepsilon_{0} R\) (capacity of spherical conductor) \(\mathrm{R}=\frac{16 \times 10^{-12}}{9} \times \frac{1}{4 \pi \varepsilon_{0}}\)…
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