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JEE Mains · Physics · STD 12 - Current electricity
  • JEE Mains 2023
  • Easy
  • MCQ

Ratio of thermal energy released in two resistor \(R\) and \(3 R\) connected in parallel in an electric circuit is :

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Answer & Solution

Correct Answer

(A) \(3: 1\)

Step-by-step Solution

Detailed explanation

\(H =\frac{ V ^2}{ R } \times t\)

\(\frac{ H _1}{ H _2}=\frac{\frac{ V ^2 t }{ R }}{\frac{ V ^2 t }{3 R }}=3: 1\)

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