JEE Mains · Physics · STD 12 - 3. current electricity
Ratio of thermal energy released in two resistor \(R\) and \(3 R\) connected in parallel in an electric circuit is :
- A \(3: 1\)
- B \(1: 1\)
- C \(1: 3\)
- D \(1: 27\)
Answer & Solution
Correct Answer
(A) \(3: 1\)
Step-by-step Solution
Detailed explanation
\(H =\frac{ V ^2}{ R } \times t\) \(\frac{ H _1}{ H _2}=\frac{\frac{ V ^2 t }{ R }}{\frac{ V ^2 t }{3 R }}=3: 1\)
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