JEE Mains · Physics · STD 12 - 11. Dual nature of radiation and matter
When a metal surface is illuminated by light of wavelength \(\lambda\), the stopping potential is \(8 \mathrm{~V}\). When the same surface is illuminated by light of wavelength \(3 \lambda\), stopping potential is \(2 \mathrm{~V}\). The threshold wavelength for this surface is _______.
- A \(5 \lambda\)
- B \(3 \lambda\)
- C \(9 \lambda\)
- D \(4.5 \lambda\)
Answer & Solution
Correct Answer
(C) \(9 \lambda\)
Step-by-step Solution
Detailed explanation
\(\mathrm{E}=\phi+\mathrm{K}_{\max }\) \(\phi=\frac{\mathrm{hc}}{\lambda_0}\) \(\mathrm{K}_{\max }=\mathrm{eV}_0\) \(8 \mathrm{e}=\frac{\mathrm{hc}}{\lambda}-\frac{\mathrm{hc}}{\lambda_0} \ldots . . \text { (i) }\)…
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