JEE Mains · Physics · STD 12 - 2. Electric potential and capacitance
There is a uniform electrostatic field in a region. The potential at various points on a small sphere centred at \(P\), in the region, is found to vary between in the limits \(589.0\,V\) to \(589.8\, V\). What is the potential at a point on the sphere whose radius vector makes an angle of \(60^o\) with the direction of the field ?........\(V\)
- A \(589.5\)
- B \(589.2\)
- C \(589.4\)
- D \(589.6\)
Answer & Solution
Correct Answer
(C) \(589.4\)
Step-by-step Solution
Detailed explanation
Potential gradient is given by, \(\Delta \mathrm{V}=\mathrm{E} . \mathrm{d}\) \(0.8=\mathrm{Ed}(\mathrm{max})\) \(\Delta V=E d \cos \theta=0.8 \times \cos 60=0.4\) Hence, maximum potential at a point on the sphere \(=589.4\, \mathrm{V}\)
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