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JEE Mains · Physics · STD 12 - Semicondutor electronics
  • JEE Mains 2022
  • Easy
  • Numerical

The energy band gap of semiconducting material to produce violet (wavelength \(=4000 \,A^{\circ}\) ) LED is \(.......eV\). (Round off to the nearest integer).

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Answer & Solution

Correct Answer

(A) \(3\)

Step-by-step Solution

Detailed explanation

\(E _{ g }=\frac{ hc }{\lambda}=\frac{1242}{\lambda( nm )}=\frac{1242}{400}=3.105\)

Answer rounded to \(3\,eV\)

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