JEE Mains · Physics · STD 11 - 12 . kinetic theory of gases
If the r.m.s. speed of chlorine molecule is \(490\,m / s\) at \(27^{\circ}\,C\), the r.m.s. speed of argon molecules at the same temperature will be \(......\,m/s\) (Atomic mass of argon \(=39.9\,u\), molecular mass of chlorine \(=70.9\,u )\)
- A \(751.7\)
- B \(451.7\)
- C \(651.7\)
- D \(551.7\)
Answer & Solution
Correct Answer
(C) \(651.7\)
Step-by-step Solution
Detailed explanation
\(V _{ rms }=\sqrt{\frac{3 RT }{ M }} \quad \frac{ v _{ Ar }}{ v _{ Cl }}=\sqrt{\frac{ M _{ Cl }}{ M _{ Ar }}}\) \(\Rightarrow v _{ Ar }=1.33 \times 490=651.7\,m / s\)
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