JEE Mains · Physics · STD 12 -Electromagnetic induction
- JEE Mains 2022
- Medium
- Numerical
The current in a coil of self inductance \(2.0 \,H\) is increasing according to \(I =2 \sin \left( t ^{2}\right) A\). The amount of energy spent during the period when current changes from \(0\) to \(2\, A\) is......\(J.\)
Pick an option to check your answer.
Answer & Solution
Correct Answer
(A) \(4\)
Step-by-step Solution
Detailed explanation
\(I =2 \sin \left( t ^{2}\right) \Rightarrow dI =4 t \sin \left( t ^{2}\right) dt\)
If \(I =0 \Rightarrow t =0\)
and \(I=2 \Rightarrow 2=2 \sin t^{2}\)
\(\Rightarrow t =\sqrt{\frac{\pi}{2}}\)
\(E =\int LI dI\)
\(=\int 2 \times 2 \sin \left( t ^{2}\right) \times 4 t \cos \left( t ^{2}\right) dt\)
\(=8 \int_{0}^{\sqrt{\pi / 2}} t \sin \left(2 t^{2}\right) d t\)
\(=2\left[-\cos \left(2 t^{2}\right)\right]_{0}^{\sqrt{\pi / 2}}\)
\(=2[-\cos \pi+\cos 0]=4\)
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