JEE Mains · Physics · STD 11 - 11. thermodynamics

A thermodynamic system is taken from an original state \(A\) to an intermediate state \(B\) by a linear process as shown in the figure. It's volume is then reduced to the original value from \(B\) to \(C\) by an isobaric process. The total work done by the gas from \(A\) to \(B\) and \(B\) to \(C\) would be :

A \(33800 \mathrm{~J}\)
B \(2200 \mathrm{~J}\)
C \(800 \mathrm{~J}\)
D \(1200 \mathrm{~J}\)

Verified Solution

Answer & Solution

Correct Answer

(C) \(800 \mathrm{~J}\)

Step-by-step Solution

Detailed explanation

Work done \(\mathrm{AB}=\frac{1}{2}(8000+6000)\) Dyne \(/ \mathrm{cm}^2 \times\) \(4 \mathrm{~m}^3=\left(6000 \mathrm{Dyne} / \mathrm{cm}^2\right) \times 4 \mathrm{~m}^3\) Work done \(\mathrm{BC}=-\left(4000\right.\) Dyne \(\left./ \mathrm{cm}^2\right) \times 4 \mathrm{~m}^3\)…

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

Same subject

Match List \(− I\) (Event) with List \(−II \) (Order of the time interval for happening of the event) and select the correct option from the options given below the lists

List \(- I\)	List \(- II\)
\((1)\) Rotation period of earth	\((i)\) \(10^5\, s\)
\((2)\) Revolution period of earth	\((ii)\) \(10^7\, s\)
\((3)\) Period of light wave	\((iii)\) \(10^{-15}\, s\)
\((4)\) Period of sound wave	\((iv)\) \(10^{-3}\, s\)

JEE Mains 2014 Medium

Explore more questions on app

From JEE Mains

Explore more questions on app