JEE Mains · Physics · STD 12 - 10. Wave optics
When a polaroid sheet is rotated between two crossed polaroids then the transmitted light intensity will be maximum for a rotation of :
- A \(60^{\circ}\)
- B \(30^{\circ}\)
- C \(90^{\circ}\)
- D \(45^{\circ}\)
Answer & Solution
Correct Answer
(D) \(45^{\circ}\)
Step-by-step Solution
Detailed explanation
Let \(I_0\) be intensity of unpolarised light incident on first polaroid. \(I_1=\) Intensity of light transmitted from \(1^{\text {st }}\) polaroid \(=\frac{I_0}{2}\) \(\theta\) be the angle between \(1^{\text {st }}\) and \(2^{\text {nd }}\) polaroid \(\phi\) be the angle…
See the Complete Solution
Get step-by-step explanations for this and 2.5 Lakh+ more JEE, NEET & CET questions.
- Unlock all solutions
- Practice the full chapter
- Track accuracy across PYQs
4.8 rated on Google Play · 14,000+ reviews
More questions from Physics
- Diameter of a steel ball is measured using a Vernier callipers which has divisions of \(0. 1\,cm\) on its main scale \((MS)\) and \(10\) divisions of its vernier scale \((VS)\) match \(9\) divisions on the main scale. Three such measurements for a ball are given as
If the zero error is \(- 0.03\,cm,\) then mean corrected diameter is ........... \(cm\)S.No. \(MS\;(cm)\) \(VS\) divisions \((1)\) \(0.5\) \(8\) \((2)\) \(0.5\) \(4\) \((3)\) \(0.5\) \(6\) JEE Mains 2015 Medium - The equation of stationary wave is \(\mathrm{y}=2 \mathrm{a} \sin \left(\frac{2 \pi \mathrm{nt}}{\lambda}\right) \cos \left(\frac{2 \pi \mathrm{x}}{\lambda}\right)\) Which of the following is NOT correct?JEE Mains 2024 Hard
- The angular momentum of an electron in a hydrogen atom is proportional to _______. (Where \(\mathrm{r}\) is the radius of orbit of electron)JEE Mains 2024 Hard
- An electric dipole is formed by two equal and opposite charges \(q\) with separation \(d\). The charges the same mass \(m\). It is kept in a uniform electric field \(E\). If it slightly rotated from its equilibrium orientation, then its angular frequency \(\omega \) isJEE Mains 2019 Hard
- Match List\(-I\) with List\(-II:\)
Choose the correct answer from the options given below:List\(-I\) List\(-II\) \((A)\) \(3\) Translational degrees of freedom \((I)\) Monoatomic gases \((B)\) \(3\) Translational,\(2\) rotational degrees of freedoms \((II)\) Polyatomic gases \((C)\) \(3\) Translational,\(2\) rotational and \(1\) vibrational degrees of freedom \((III)\) Rigid diatomic gases \((D)\) \(3\) Translational,\(3\) rotational and more than one vibrational degrees of freedom \((IV)\) Nonrigid diatomic gases JEE Mains 2023 Medium - The equivalent resistance between points \(A\) and \(B\) in the given network is ............ \(\Omega\)
JEE Mains 2022 Medium
More PYQs from JEE Mains
- The system of equations
\(\begin{aligned}
& x+y+z=6 \\
& x+2 y+5 z=9, \\
& x+5 y+\lambda z=\mu,
\end{aligned}\) has no solution ifJEE Mains 2025 Easy - Area (in sq. units) of the region outside \(\frac{|\mathrm{x}|}{2}+\frac{|\mathrm{y}|}{3}=1\) and inside the ellipse \(\frac{\mathrm{x}^{2}}{4}+\frac{\mathrm{y}^{2}}{9}=1\) isJEE Mains 2020 Medium
- You are asked to design a shaving mirror assuming that a person keeps it \(10\,cm\) from his face and views the magnified image of the face at the closest comfortable distance of \(25\,cm.\) The radius of curvature of the mirror would then be.....\(cm\)JEE Mains 2015 Medium
- The sum of all real values of \(x\) satisfying the equation \({\left( {{x^2} - 5x + 5} \right)^{{x^2} + 4x - 60}} = 1\) is ;JEE Mains 2016 Hard
- A person observes two moving trains, '\(A\)' reaching the station and '\(B\)' leaving the station with equal speed of \(30\,m / s\). If both trains emit sounds with frequency \(300\,Hz\), (Speed of sound : \(330\,m / s\) ) approximate difference of frequencies heard by the person will be \(..........Hz\)JEE Mains 2023 Medium
- The shortest distance between the lines \(\frac{x-3}{2}=\frac{y-2}{3}=\frac{z-1}{-1}\) and \(\frac{x+3}{2}=\frac{y-6}{1}=\frac{z-5}{3}\) isJEE Mains 2022 Medium