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JEE Mains · Physics · STD 12 - Current electricity
  • JEE Mains 2023
  • Hard
  • Numerical

The current flowing through a conductor connected across a source is \(2\,A\) and \(1.2\,A\) at \(0^{\circ}\,C\) and \(100^{\circ}\,C\) respectively. The current flowing through the conductor at \(50^{\circ}\,C\) will be \(......\times 10^2\,mA\).

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Answer & Solution

Correct Answer

(D) \(15\)

Step-by-step Solution

Detailed explanation

\(i_0 R_0=i_{100} R_{100} \quad\) [For same source]

\(\Rightarrow 2 R_0=1.2 R_0[1+100 \alpha]\)

\(\Rightarrow 1+100 \alpha=\frac{5}{3} \Rightarrow 100 \alpha=\frac{2}{3}\)

\(\Rightarrow 50 \alpha=\frac{1}{3}\)

\(\therefore i_{50} R_{50}=i_0 R_0\)

\(\Rightarrow i_{50}=\frac{i_0 R_0}{R_{50}}=\frac{2 \times R_0}{R_0(1+50 \alpha)}=\frac{2}{1+\frac{1}{3}}=1.5\,A\)

\(=15 \times 10^2\,mA\)

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