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JEE Mains · Physics · STD 12 - Current electricity
  • JEE Mains 2023
  • Medium
  • MCQ

The charge flowing in a conductor changes with time as \(Q ( t )=\alpha t -\beta t ^2+\gamma t ^3\). Where \(\alpha, \beta\) and \(\gamma\) are constants. Minimum value of current is :

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Answer & Solution

Correct Answer

(D) \(\alpha-\frac{\beta^2}{3 \gamma}\)

Step-by-step Solution

Detailed explanation

\(Q=\left(\alpha t-\beta t^2+\gamma t^3\right)\)

\(i=\frac{d Q}{d t}=\left(\alpha-2 \beta t+3 \gamma t^2\right)\)

\(\frac{d i}{d t}=(3 \gamma t-2 \beta)=0\)

\(\Rightarrow t=\frac{\beta}{3 \gamma}\)

\(i=\left(\alpha-2 \beta t+3 \gamma t^2\right)=\left(\alpha-\frac{\beta^2}{3 \gamma}\right)\)

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