JEE Mains · Physics · STD 11 - 9.1 fluid mechanics
An ideal fluid flows (laminar flow) through a pipe of non-uniform diameter. The maximum and minimum diameters of the pipes are \(6.4 \;\mathrm{cm}\) and \(4.8 \;\mathrm{cm},\) respectively. The ratio of the minimum and the maximum velocities of fluid in this pipe is:
- A \(\frac{\sqrt{3}}{2}\)
- B \(\frac{{3}}{4}\)
- C \(\frac{{81}}{256}\)
- D \(\frac{{9}}{16}\)
Answer & Solution
Correct Answer
(D) \(\frac{{9}}{16}\)
Step-by-step Solution
Detailed explanation
\(\mathrm{A}_{1} \mathrm{v}_{1}=\mathrm{A}_{2} \mathrm{v}_{2}\) \(\frac{V_{\min }}{V_{\max }}=\frac{A_{\min }}{A_{\max }}\) \(\frac{v_{\min }}{v_{\max }}=\left(\frac{4.8}{6.4}\right)^{2}\) \(\frac{V_{\min }}{V_{\max }}=\frac{9}{16}\)
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