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JEE Mains · Physics · STD 11 - Work,energy,power and collision
  • JEE Mains 2020
  • Medium
  • Numerical

A particle \((\mathrm{m}=1\; \mathrm{kg})\) slides down a frictionless track \((AOC)\) starting from rest at a point \(A\) (height \(2\; \mathrm{m}\) ). After reaching \(\mathrm{C}\), the particle continues to move freely in air as a projectile. When it reaching its highest point \(P\) (height \(1 \;\mathrm{m}\) ). the kinetic energy of the particle (in \(\mathrm{J}\) ) is : (Figure drawn is schematic and not to scale; take \(\left.g=10 \;\mathrm{ms}^{-2}\right)\)

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Answer & Solution

Correct Answer

(B) \(10\)

Step-by-step Solution

Detailed explanation

Mechanical energy conservation between

\(A\;and\;P\)

\(\mathrm{U}_{1}+\mathrm{K}_{1}(=0)=\mathrm{K}_{2}+\mathrm{U}_{2}\)

\(\mathrm{mg} \times 2=\mathrm{mg} \times 1+\mathrm{K}_{2}\)

\(\mathrm{K}_{2}=\mathrm{mg} \times 1=10 \mathrm{J}\)

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