JEE Mains · Physics · STD 11 - 5. work,energy,power and collision
A particle \((\mathrm{m}=1\; \mathrm{kg})\) slides down a frictionless track \((AOC)\) starting from rest at a point \(A\) (height \(2\; \mathrm{m}\) ). After reaching \(\mathrm{C}\), the particle continues to move freely in air as a projectile. When it reaching its highest point \(P\) (height \(1 \;\mathrm{m}\) ). the kinetic energy of the particle (in \(\mathrm{J}\) ) is : (Figure drawn is schematic and not to scale; take \(\left.g=10 \;\mathrm{ms}^{-2}\right)\)

- A \(8\)
- B \(10\)
- C \(15\)
- D \(13\)
Answer & Solution
Correct Answer
(B) \(10\)
Step-by-step Solution
Detailed explanation
Mechanical energy conservation between \(A\;and\;P\) \(\mathrm{U}_{1}+\mathrm{K}_{1}(=0)=\mathrm{K}_{2}+\mathrm{U}_{2}\) \(\mathrm{mg} \times 2=\mathrm{mg} \times 1+\mathrm{K}_{2}\) \(\mathrm{K}_{2}=\mathrm{mg} \times 1=10 \mathrm{J}\)
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