JEE Mains · Maths · STD 12 - 7.2 definite integral
Let \(f : R \rightarrow R\) be a differentiable function such that \(f \left(\frac{\pi}{4}\right)=\sqrt{2}, f \left(\frac{\pi}{2}\right)=0\) and \(f ^{\prime}\left(\frac{\pi}{2}\right)=1\) and let \(g(x)=\int\limits_{x}^{\pi / 4}\left(f^{\prime}(t) \sec t+\tan t \operatorname{sectf}(t)\right) d t\) for \(x \in\left[\frac{\pi}{4}, \frac{\pi}{2}\right)\). Then \(\lim\limits _{ x \rightarrow\left(\frac{\pi}{2}\right)^{-}} g ( x )\) is equal to
- A \(2\)
- B \(3\)
- C \(4\)
- D \(-3\)
Answer & Solution
Correct Answer
(B) \(3\)
Step-by-step Solution
Detailed explanation
\(g(x)=\int\limits_{x}^{\pi / 4}\left(f^{\prime}(t) \sec t+\tan t \sec t f(t)\right) d t\) \(g(x)=\int\limits_{x}^{\pi / 4} d ( f ( t ) \cdot \sec t )=\left. f ( t ) \operatorname{sect}\right|_{ x } ^{\pi / 4}\)…
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