JEE Mains · Physics · STD 12 - 14. Semicondutor electronics
The Boolean expression \(\mathrm{Y}=\mathrm{A} \overline{\mathrm{B}} \mathrm{C}+\overline{\mathrm{A}} \overline{\mathrm{C}}\) can be realised with which of the following gate configurations.
A. One 3-input AND gate, 3 NOT gates and one 2input OR gate, One 2-input AND gate,
B. One 3-input AND gate, 1 NOT gate, One 2input NOR gate and one 2-input OR gate
C. 3-input OR gate, 3 NOT gates and one 2-input AND gate
Choose the correct answer from the options given below.
- A B, C Only
- B A,B Only
- C A, B, C Only
- D A, C Only
Answer & Solution
Correct Answer
(B) A,B Only
Step-by-step Solution
Detailed explanation
\(\because \overline{\mathrm{A}} \cdot \overline{\mathrm{C}}+\overline{\mathrm{A}+\mathrm{C}} \equiv \mathrm{NOR}\) gate
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