JEE Mains · Physics · STD 11 - Oscillations
- JEE Mains 2023
- Medium
- Numerical
A particle of mass \(250\,g\) executes a simple harmonic motion under a periodic force \(F =(-25\,x) N\). The particle attains a maximum speed of \(4\,m / s\) during its oscillation. The amplitude of the motion is \(...........cm\).
Pick an option to check your answer.
Answer & Solution
Correct Answer
(B) \(40\)
Step-by-step Solution
Detailed explanation
\(\frac{1}{4} a =-25 x \quad ; \quad a =-100 x\)
\(\omega^2=100 \quad \omega=10\)
\(\omega A =4\) \(\quad A=\frac{4}{10}=0.4\,m\)
\(A =40\,cm\)
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