JEE Mains · Physics · STD 11 - 13. oscillations
A particle of mass \(250\,g\) executes a simple harmonic motion under a periodic force \(F =(-25\,x) N\). The particle attains a maximum speed of \(4\,m / s\) during its oscillation. The amplitude of the motion is \(...........cm\).
- A \(20\)
- B \(40\)
- C \(60\)
- D \(80\)
Answer & Solution
Correct Answer
(B) \(40\)
Step-by-step Solution
Detailed explanation
\(\frac{1}{4} a =-25 x \quad ; \quad a =-100 x\) \(\omega^2=100 \quad \omega=10\) \(\omega A =4\) \(\quad A=\frac{4}{10}=0.4\,m\) \(A =40\,cm\)
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