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JEE Mains · Physics · STD 11 - Oscillations
  • JEE Mains 2023
  • Medium
  • Numerical

A particle of mass \(250\,g\) executes a simple harmonic motion under a periodic force \(F =(-25\,x) N\). The particle attains a maximum speed of \(4\,m / s\) during its oscillation. The amplitude of the motion is \(...........cm\).

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Answer & Solution

Correct Answer

(B) \(40\)

Step-by-step Solution

Detailed explanation

\(\frac{1}{4} a =-25 x \quad ; \quad a =-100 x\)

\(\omega^2=100 \quad \omega=10\)

\(\omega A =4\) \(\quad A=\frac{4}{10}=0.4\,m\)

\(A =40\,cm\)

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