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JEE Mains · Physics · STD 11 - Units,dimensions and measurement
  • JEE Mains 2022
  • Medium
  • MCQ

If momentum \([ P ]\), area \([ A ]\) and time \([ T ]\) are taken as fundamental quantities, then the dimensional formula for coefficient of viscosity is :

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Answer & Solution

Correct Answer

(A) \(\left[ PA ^{-1} T ^{0}\right]\)

Step-by-step Solution

Detailed explanation

Viscosity \(=\) pascal.second

\(P ^{ x } A ^{ y } T ^{z}=\left[ M ^{1} L ^{-1} T ^{-1}\right]\)

\(\left[ M ^{1} L ^{+1} T ^{-1}\right]^{ x }\left[ L ^{2}\right]^{y}\left[ T ^{1}\right]^{z}= M ^{1} L ^{-1} T ^{-1}\)

\(M ^{ x } L ^{+ x +2 y } T ^{- x + z }= M ^{1} L ^{-1} T ^{-1}\)

\(x=1 \quad x+2 y=-1 \quad-x+z=-1\)

\(y=-1\)

\(z=0\)

Viscosity \(= P ^{1} A ^{-1} T ^{0}\)

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