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JEE Mains · Physics · STD 11 - Motion in straight line
  • JEE Mains 2023
  • Medium
  • Numerical

A ball is thrown vertically upward with an initial velocity of \(150\,m / s\). The ratio of velocity after \(3\,s\) and \(5\,s\) is \(\frac{x+1}{x}\). The value of \(x\) is \(...........\) Take \(\left(g=10\,m / s ^2\right)\)

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Answer & Solution

Correct Answer

(B) \(5\)

Step-by-step Solution

Detailed explanation

\(\overrightarrow{ V }=\overrightarrow{ u }+\overrightarrow{ a t}\)

\(V =150-10 t\)

\(V (3)=150-30=120\)

\(V (5)=150-50=100\)

\(\frac{120}{100}=\frac{ x +1}{ x }=\frac{6}{5} \Rightarrow x =5\)

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