JEE Mains · Physics · STD 11 - Motion in straight line
- JEE Mains 2023
- Medium
- Numerical
A ball is thrown vertically upward with an initial velocity of \(150\,m / s\). The ratio of velocity after \(3\,s\) and \(5\,s\) is \(\frac{x+1}{x}\). The value of \(x\) is \(...........\) Take \(\left(g=10\,m / s ^2\right)\)
Pick an option to check your answer.
Answer & Solution
Correct Answer
(B) \(5\)
Step-by-step Solution
Detailed explanation
\(\overrightarrow{ V }=\overrightarrow{ u }+\overrightarrow{ a t}\)
\(V =150-10 t\)
\(V (3)=150-30=120\)
\(V (5)=150-50=100\)
\(\frac{120}{100}=\frac{ x +1}{ x }=\frac{6}{5} \Rightarrow x =5\)
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