JEE Mains · Physics · STD 11- Mechanical properties of solids
- JEE Mains 2022
- Medium
- MCQ
The area of cross section of the rope used to lift a load by a crane is \(2.5 \times 10^{-4} m ^{2}\). The maximum lifting capacity of the crane is \(10\) metric tons. To increase the lifting capacity of the crane to \(25\) metric tons, the required area of cross section of the rope should be.\(.........\times 10^{-4} \,m ^{2}\) (take \(g =10\, ms ^{-2}\) )
Pick an option to check your answer.
Answer & Solution
Correct Answer
(A) \(6.25\)
Step-by-step Solution
Detailed explanation
Since breaking stress (Maximum lifting capacity) is the property of material so it will remain same. breaking stress \(=\frac{\text { Maximum lifting capacity }}{\text { Area of cross section of rope }}\) \(\frac{10}{2.5 \times 10^{-4}}=\frac{25}{ A }\)
\(A =625 \times 10^{-6}\)
\(=6.25 \times 10^{-4} m ^{2}\)
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