In a parallel plate capacitor set up, the plate area of capacitor is \(2 \,m ^{2}\) and the plates are separated by \(1\, m\). If the space between the plates are filled with a dielectric material of thickness \(0.5\, m\) and area \(2\, m ^{2}\) (see \(fig.\)) the capacitance of the set-up will be \(.........\, \varepsilon_{0}\) (Dielectric constant of the material \(=3.2\) ) and (Round off to the Nearest Integer)

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Correct Answer

(C) \(3\)

Detailed explanation

\(C=\frac{\varepsilon_{0} A }{\frac{ d }{2 K }+\frac{ d }{2}}=\frac{2 \varepsilon_{0} A }{\frac{ d }{ K }+ d }\)

\(=\frac{2 \times 2 \varepsilon_{0}}{\frac{1}{3.2}+1}=\frac{4 \times 3.2}{4.2} \varepsilon_{0}\)

\(=3.04 \,\varepsilon_{0}\)

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