JEE Mains · Physics · STD 12 - 10. Wave optics
The value of numerical aperature of the objective lens of a microscope is \(1.25\). If light of wavelength \(5000\,\mathop A\limits^o \) is used, the minimum separation between two points, to be seen as distinct, will be....\(\mu m\)
- A \(0.48\)
- B \(0.38\)
- C \(0.24\)
- D \(0.12\)
Answer & Solution
Correct Answer
(C) \(0.24\)
Step-by-step Solution
Detailed explanation
Numerical aperature of the microscope is given as \({\text{NA}} = \frac{{0.61\,\lambda }}{{\text{d}}}\) Where \(\mathrm{d}=\) minimum sparaton between two points to be seen as distinct \({\text{d}} = \frac{{0.61\,\,\lambda }}{{{\text{NA}}}} = \)…
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