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JEE Mains · Physics · STD 12 - 4. Moving charges and magnetism

A charge \(q\)  is spread uniformly over an insulated loop of radius \(r\) . If it is rotated with an angular velocity \(\omega \) with respect to normal axis then the magnetic moment of the loop is

  1. A \(\frac{1}{2}\,\,q\omega {r^2}\)
  2. B \(\frac{4}{3}\,\,q\omega {r^2}\)
  3. C \(\frac{3}{2}\,\,q\omega {r^2}\)
  4. D \(q\omega {r^2}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\frac{1}{2}\,\,q\omega {r^2}\)

Step-by-step Solution

Detailed explanation

Magnetic moment, \(\mu \, = \,IA\, = \,\frac{{qv}}{{2\pi r}}(\pi {r^2})\) or, \(\mu \,\, = \,\,\frac{{qr\omega }}{{2\pi r}}(\pi {r^2})\, = \,\frac{1}{2}\,q{r^2}\omega \)
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