A charge q is spread uniformly over an insulated loop of radius r. If it is rotated with an angular velocity with respect to normal axis then the magnetic moment of the loop is

(B) \frac{4}{3}\,\,q\omega {r^2}

(C) \frac{3}{2}\,\,q\omega {r^2}

JEE Mains · Physics · STD 12 - Moving charges and magnetism

A charge \(q\) is spread uniformly over an insulated loop of radius \(r\) . If it is rotated with an angular velocity \(\omega \) with respect to normal axis then the magnetic moment of the loop is

Pick an option to check your answer.

Verified Solution

Correct Answer

(A) \(\frac{1}{2}\,\,q\omega {r^2}\)

Detailed explanation

Magnetic moment, \(\mu \, = \,IA\, = \,\frac{{qv}}{{2\pi r}}(\pi {r^2})\)

or, \(\mu \,\, = \,\,\frac{{qr\omega }}{{2\pi r}}(\pi {r^2})\, = \,\frac{1}{2}\,q{r^2}\omega \)

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