JEE Mains · Physics · STD 11 - System of particles and rotational motion
- JEE Mains 2023
- Medium
- Numerical
A ring and a solid sphere rotating about an axis passing through their centers have same radii of gyration. The axis of rotation is perpendicular to plane of ring. The ratio of radius of ring to that of sphere is \(\sqrt{\frac{2}{x}}\). The value of \(x\) is \(.......\)
Pick an option to check your answer.
Answer & Solution
Correct Answer
(C) \(5\)
Step-by-step Solution
Detailed explanation
For ring \(I=m R_1^2=m K_1^2\)
\(\therefore\) Radius of gyration \(K_1=R_1\)
For solid sphere
\(I^{\prime}=\frac{2}{5} m^{\prime} R_2^2=m^{\prime} K_2^2\)
\(\therefore \text { Its radius of gyration }=K_2=\sqrt{\frac{2}{5}} R_2\)
\(\because K_1=K_2\)
\(\therefore R_1=\sqrt{\frac{2}{5}} R_2\)
\(\therefore \frac{R_1}{R_2}=\sqrt{\frac{2}{5}}\)
\(\therefore x=5\)
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