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JEE Mains · Physics · STD 11 - Thermodynamics
  • JEE Mains 2021
  • Medium
  • Numerical

One mole of an ideal gas at \(27^{\circ} {C}\) is taken from \({A}\) to \({B}\) as shown in the given \({PV}\) indicator diagram. The work done by the system will be \(......\times 10^{-1} \,{J}\) [Given : \(R=8.3\, {J} /\,mole\,{K}, \ln 2=0.6931\) ] (Round off to the nearest integer)

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Answer & Solution

Correct Answer

(D) \(17258\)

Step-by-step Solution

Detailed explanation

Process of isothermal

\(W=n R T \ln \left(\frac{V_{2}}{V_{1}}\right)\)

\(1 \times 8.3 \times 300 \times \ln 2\)

\(=17258 \times 10^{-1} {J}\)

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