JEE Mains · Physics · STD 11 - Thermodynamics
- JEE Mains 2021
- Medium
- Numerical
One mole of an ideal gas at \(27^{\circ} {C}\) is taken from \({A}\) to \({B}\) as shown in the given \({PV}\) indicator diagram. The work done by the system will be \(......\times 10^{-1} \,{J}\) [Given : \(R=8.3\, {J} /\,mole\,{K}, \ln 2=0.6931\) ] (Round off to the nearest integer)

Pick an option to check your answer.
Answer & Solution
Correct Answer
(D) \(17258\)
Step-by-step Solution
Detailed explanation
Process of isothermal
\(W=n R T \ln \left(\frac{V_{2}}{V_{1}}\right)\)
\(1 \times 8.3 \times 300 \times \ln 2\)
\(=17258 \times 10^{-1} {J}\)
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