JEE Mains · Physics · STD 12 - 3. current electricity
Two identical heater filaments are connected first in parallel and then in series. At the same applied voltage, the ratio of heat produced in same time for parallel to series will be:
- A \(4: 1\)
- B \(2: 1\)
- C \(1: 2\)
- D \(1: 4\)
Answer & Solution
Correct Answer
(A) \(4: 1\)
Step-by-step Solution
Detailed explanation
Parallel combination \(H _{ p }=\left[\frac{ V ^2}{\left(\frac{ R }{2}\right)}\right) t =\frac{2 V ^2 t }{ R }\) Series combination \(H _s=\left(\frac{ V ^2}{2 R }\right) t \quad \therefore \frac{ H _{ p }}{ H _{ s }}=4\)
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