The displacement x versus time graph is shown below.

(A) The average velocity during 0 to 3 s is \(10 \mathrm{~m} / \mathrm{s}\)
(B) The average velocity during 3 to 5 s is \(0 \mathrm{~m} / \mathrm{s}\)
(C) The instantaneous velocity at \(\mathrm{t}=2 \mathrm{~s}\) is \(5 \mathrm{~m} / \mathrm{s}\)
(D) The average velocity during 5 to 7 s and instantaneous velocity at \(\mathrm{t}=6.5 \mathrm{~s}\) are equal
(E) The average velocity from \(t=0\) to \(t=9 \mathrm{~s}\) is zero
Choose the correct answer from the options given below:

\(\begin{aligned}
& \langle\overrightarrow{\mathrm{v}}\rangle=\frac{\Delta \overrightarrow{\mathrm{s}}}{\Delta \mathrm{t}}=\frac{\mathrm{S}_{\mathrm{f}}-\mathrm{S}_{\mathrm{i}}}{\mathrm{t}_{\mathrm{f}}-\mathrm{t}_{\mathrm{i}}} \\
& \overrightarrow{\mathrm{v}}=\frac{\mathrm{ds}}{\mathrm{dt}}=\text { slope }
\end{aligned}\)
(A) 0 to \(3 \mathrm{sec} ;\langle\overrightarrow{\mathrm{v}}\rangle=\frac{5-0}{3}=5 / 3 \mathrm{~m} / \mathrm{s}\)
(B) 0 to \(5 \mathrm{sec} ;\langle\vec{v}\rangle=\frac{5-5}{2}=0\)
(C) \(\mathrm{t}=2 ;\) slope \(=\vec{v}=5 \mathrm{~m} / \mathrm{s}\)
(D) \(\mathfrak{t}=5\) to \(7 \mathrm{sec} ;\langle\overrightarrow{\mathrm{v}}\rangle=\frac{0-5}{2}=-2.5 \mathrm{~m} / \mathrm{s}\)
At \(t=6.5 \mathrm{sec} ; \vec{v}=10\)
(E) \(\mathrm{t}=0\) to \(\mathrm{t}=9 ;\langle\overrightarrow{\mathrm{v}}\rangle=0\)