JEE Mains · Physics · STD 11 - 1. units,dimensions and measurement
What is the dimensional formula of \(a b^{-1}\) in the equation? \(\left(\mathrm{P}+\frac{\mathrm{a}}{\mathrm{V}^2}\right)(\mathrm{V}-\mathrm{b})=\mathrm{RT}\), where letters have their usual meaning.
- A \(\left[\mathrm{M}^6 \mathrm{~L}^3 \mathrm{~T}^{-2}\right]\)
- B \(\left[\mathrm{ML}^2 \mathrm{~T}^{-2}\right]\)
- C \(\left[M^{-1} L^j T^3\right]\)
- D \(\left[M^6 L^7 T^4\right]\)
Answer & Solution
Correct Answer
(B) \(\left[\mathrm{ML}^2 \mathrm{~T}^{-2}\right]\)
Step-by-step Solution
Detailed explanation
\(\because[\mathrm{V}]=[\mathrm{b}]\) \(\therefore \text { Dimension of } \mathrm{b}=\left[\mathrm{L}^3\right]\) \(\&[\mathrm{P}]=\left[\frac{\mathrm{a}}{\mathrm{V}^2}\right]\)…
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