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JEE Mains · Physics · STD 11 - Newtons laws of motion
  • JEE Mains 2013
  • Hard
  • MCQ

A uniform sphere of weight \(W\) and radius \(5\, cm\) is being held by a string as shown in the figure. The tension in the string will be

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Answer & Solution

Correct Answer

(D) \(\frac{13}{12}\,W\)

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Detailed explanation

\(\begin{array}{l}
PQ = \sqrt {O{P^2} + O{Q^2}} \\
 = \sqrt {{{13}^2} + {5^2}}  = 12\\
Tension\,in\,the\,string\,T,\,so,\,T\cos \theta  = w\\
 \Rightarrow T = \frac{w}{{\cos \theta }} = \frac{{13}}{{12}}W
\end{array}\)
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