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JEE Mains · Physics · STD 11 - 4.1 newtons laws of motion
A uniform sphere of weight \(W\) and radius \(5\, cm\) is being held by a string as shown in the figure. The tension in the string will be
- A \(\frac{12}{5}\,W\)
- B \(\frac{5}{12}\,W\)
- C \(\frac{13}{5}\,W\)
- D \(\frac{13}{12}\,W\)
Answer & Solution
Correct Answer
(D) \(\frac{13}{12}\,W\)
Step-by-step Solution
Detailed explanation
\(\begin{array}{l} PQ = \sqrt {O{P^2} + O{Q^2}} \\ = \sqrt {{{13}^2} + {5^2}} = 12\\ Tension\,in\,the\,string\,T,\,so,\,T\cos \theta = w\\ \Rightarrow T = \frac{w}{{\cos \theta }} = \frac{{13}}{{12}}W \end{array}\)
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