JEE Mains · Physics · STD 12 - 3. current electricity
Consider an electrical circuit containing a two way switch \(^{\prime}{S}^{\prime}\). Initially \({S}\) is open and then \({T}_{1}\) is connected to \({T}_{2} .\) As the current in \({R}=6 \,\Omega\) attains a maximum value of steady state level, \({T}_{1}\) is disconnected from \({T}_{2}\) and immediately connected to \({T}_{3} .\) Potential drop across \({r}=3\, \Omega\) resistor immediately after \(T_{1}\) is connected to \(T_{3}\) is \(....\,V.\) (Round off to the Nearest Integer)
- A \(2\)
- B \(3\)
- C \(5\)
- D \(7\)
Answer & Solution
Correct Answer
(B) \(3\)
Step-by-step Solution
Detailed explanation
When \(T _{1}\) and \(T _{2}\) are connected, then the steady state current in the inductor \(I=\frac{6}{6}=1 A\) When \(T _{1}\) and \(T _{3}\) are connected then current through inductor remains same. So potential difference across \(3 \Omega\)…
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