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JEE Mains · Physics · STD 11 - Units,dimensions and measurement
  • JEE Mains 2021
  • Medium
  • Numerical

The radius of a sphere is measured to be \((7.50 \pm 0.85) \,cm .\) Suppose the percentage error in its volume is \(x\). The value of \(x\), to the nearest integer is .....\(\%\)

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Answer & Solution

Correct Answer

(B) \(34\)

Step-by-step Solution

Detailed explanation

\(\because V =\frac{4}{3} \pi r ^{3}\)

taking log and then differentiate

\(\frac{ dV }{ V }=3 \frac{ dr }{ r }\)

\(=\frac{3 \times 0.85}{7.5} \times 100\, \%=34\, \%\)

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