JEE Mains · Physics · STD 11 - 13. oscillations
A particle is executing simple harmonic motion. Its amplitude is \(A\) and time period is \(5\) sec. The time required by it to move from \(x = A\) to \(x = \dfrac{A}{\sqrt{2}}\) is _______ sec.
- A \(1/4\)
- B \(5/4\)
- C \(5/8\)
- D \(3/8\)
Answer & Solution
Correct Answer
(C) \(5/8\)
Step-by-step Solution
Detailed explanation
The equation of simple harmonic motion for a particle starting from the extreme position \(x = A\) is given by: \(x = A \cos(\omega t)\) We need to find the time \(t\) when the particle reaches \(x = \dfrac{A}{\sqrt{2}}\). Substituting this value into the equation:…
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