JEE Mains · Physics · STD 11 - Kinetic theory of gases
- JEE Mains 2023
- Medium
- MCQ
Let \(\gamma_1\) be the ratio of molar specific heat at constant pressure and molar specific heat at constant volume of a monoatomic gas and \(\gamma_2\) be the similar ratio of diatomic gas. Considering the diatomic gas molecule as a rigid rotator, the ratio, \(\frac{\gamma_1}{\gamma_2}\) is
Pick an option to check your answer.
Answer & Solution
Correct Answer
(C) \(\frac{25}{21}\)
Step-by-step Solution
Detailed explanation
For monoatomic gas
\(\gamma_1=\frac{5}{3}\)
For diatomic gas at low temperatures
\(\gamma _2=\frac{7}{5}\)
\(\therefore \frac{\gamma_1}{\gamma_2}=\frac{\frac{5}{3}}{\frac{7}{5}}=\frac{25}{21}\)
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