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JEE Mains · Physics · STD 11 - 12 . kinetic theory of gases

Let \(\gamma_1\) be the ratio of molar specific heat at constant pressure and molar specific heat at constant volume of a monoatomic gas and \(\gamma_2\) be the similar ratio of diatomic gas. Considering the diatomic gas molecule as a rigid rotator, the ratio, \(\frac{\gamma_1}{\gamma_2}\) is

  1. A \(\frac{27}{35}\)
  2. B \(\frac{35}{27}\)
  3. C \(\frac{25}{21}\)
  4. D \(\frac{21}{25}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(\frac{25}{21}\)

Step-by-step Solution

Detailed explanation

For monoatomic gas \(\gamma_1=\frac{5}{3}\) For diatomic gas at low temperatures \(\gamma _2=\frac{7}{5}\) \(\therefore \frac{\gamma_1}{\gamma_2}=\frac{\frac{5}{3}}{\frac{7}{5}}=\frac{25}{21}\)
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