JEE Mains · Physics · STD 11 - 11. thermodynamics
In the reported figure, heat energy absorbed by a system in going through a cyclic process is \(......\,\pi J\)
- A \(50\)
- B \(150\)
- C \(100\)
- D \(200\)
Answer & Solution
Correct Answer
(C) \(100\)
Step-by-step Solution
Detailed explanation
For complete cyclic process \(\Delta U=0\) \(\therefore \text { from } \Delta Q=\Delta U+W\) \(=0+W\) \(\Delta Q=W\) \(=\text { Area }\) \(=\pi r_{1} \cdot r_{2}\) \(=\pi \times\left(10 \times 10^{3}\right)\left(10 \times 10^{-3}\right)\) \(\Delta Q=100 \pi\)…
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