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JEE Mains · Physics · STD 11 - Thermodynamics
  • JEE Mains 2021
  • Medium
  • Numerical

In the reported figure, heat energy absorbed by a system in going through a cyclic process is \(......\,\pi J\)

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Answer & Solution

Correct Answer

(C) \(100\)

Step-by-step Solution

Detailed explanation

For complete cyclic process

\(\Delta U=0\)

\(\therefore \text { from } \Delta Q=\Delta U+W\)

\(=0+W\)

\(\Delta Q=W\)

\(=\text { Area }\)

\(=\pi r_{1} \cdot r_{2}\)

\(=\pi \times\left(10 \times 10^{3}\right)\left(10 \times 10^{-3}\right)\)

\(\Delta Q=100 \pi\)

\(\therefore \text { Ans. }=100\)

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