JEE Mains · Physics · STD 11 - Thermodynamics
- JEE Mains 2021
- Medium
- Numerical
In the reported figure, heat energy absorbed by a system in going through a cyclic process is \(......\,\pi J\)

Pick an option to check your answer.
Answer & Solution
Correct Answer
(C) \(100\)
Step-by-step Solution
Detailed explanation
For complete cyclic process
\(\Delta U=0\)
\(\therefore \text { from } \Delta Q=\Delta U+W\)
\(=0+W\)
\(\Delta Q=W\)
\(=\text { Area }\)
\(=\pi r_{1} \cdot r_{2}\)
\(=\pi \times\left(10 \times 10^{3}\right)\left(10 \times 10^{-3}\right)\)
\(\Delta Q=100 \pi\)
\(\therefore \text { Ans. }=100\)
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