JEE Mains · Physics · STD 11 - 11. thermodynamics
In a certain thermodynamical process, the pressure of a gas depends on its volume as \(kV ^{3}\). The work done when the temperature changes from \(100^{\circ} C\) to \(300^{\circ} C\) will be .......... \(nR\), where \(n\) denotes number of moles of a gas.
- A \(25\)
- B \(40\)
- C \(50\)
- D \(60\)
Answer & Solution
Correct Answer
(C) \(50\)
Step-by-step Solution
Detailed explanation
\(P=k V^{3}\) \(T_{i}=100^{\circ} C \) \(T _{ f }=300^{\circ} C\) \(\Delta T =300-100\) \(\Delta T =200^{\circ} C\) \(P = kV ^{3}\) now \(PV = nRT\) \(\therefore kV ^{4}= nRT\) now \(4 kV ^{3} dV = nRdT\) \(\therefore PdV = nRdT / 4\) \(\therefore\) Work…
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