JEE Mains · Physics · STD 11 - 1. units,dimensions and measurement
Match List - I with List - II.
| List-I | List-II |
|---|---|
| (A) Angular Impulse | (I) \(\left[M^0 L^2 T^{-2}\right]\) |
| (B) Latent Heat | (II) \(\left[M L^2 T^{-3} A^{-1}\right]\) |
| (C) Electrical resistivity | (III) \(\left[M L^2 T^{-1}\right]\) |
| (D) Electromotive force | (IV) \(\left[M L^3 T^{-3} A^{-2}\right]\) |
- A (A)-(II), (B)-(I), (C)-(IV), (D)-(III)
- B (A)-(I), (B)-(III), (C)-(IV), (D)-(II)
- C (A)-(III), (B)-(I), (C)-(II), (D)-(IV)
- D (A)-(III), (B)-(I), (C)-(IV), (D)-(II)
Answer & Solution
Correct Answer
(D) (A)-(III), (B)-(I), (C)-(IV), (D)-(II)
Step-by-step Solution
Detailed explanation
Angular impulse = \(\left[M L^2 T^{-1}\right]\) Latent Heat = \(\left[M^0 L^2 T^{-2}\right]\) Electrical resistivity = \(\left[M L^3 T^{-3} A^{-2}\right]\) Electromotive force = \(\left[M L^2 T^{-3} A^{-1}\right]\)
See the Complete Solution
Get step-by-step explanations for this and 2.5 Lakh+ more JEE, NEET & CET questions.
- Unlock all solutions
- Practice the full chapter
- Track accuracy across PYQs
4.8 rated on Google Play · 14,000+ reviews
More questions from Physics
- To compare EMF of two cells using potentiometer the balancing lengths obtained are 200 cm and 150 cm . The least count of scale is 1 cm . The percentage error in the ratio of EMFs is ___________.JEE Mains 2026 Medium
- A biconvex lens is formed by using two thin planoconvex lenses, as shown in the figure. The refractive index and radius of curved surfaces are also mentioned in figure. When an object is placed on the left side of lens at a distance of 30 cm from the biconvex lens, the magnification of the image will be :
JEE Mains 2026 Easy - A copper rod of cross-sectional area \(A\) carries a uniform current \(I\) through it. At temperature \(T\), if the volume charge density of the rod is \(\rho \), how long will the charges take to travel a distance \(d\) ?JEE Mains 2018 Medium
- A particle is projected with velocity \(u\) so that its horizontal range is three times the maximum height attained by it. The horizontal range of the projectile is given as \(\frac{n u^2}{25 g}\), where value of \(n\) is : (Given ' \(g\) ' is the acceleration due to gravity).JEE Mains 2025 Easy
- The energy equivalent of \(1 \mathrm{~g}\) of substance is _______.JEE Mains 2024 Medium
- The distance between an object and a screen is \(100\, cm .\) A lens can produce real image of the object on the screen for two different positions between the screen and the object. The distance between these two positions is \(40\, cm .\) If the power of the lens is close to \(\left(\frac{ N }{100}\right) D\) where \(N\) is an integer, the value of \(N\) is.......JEE Mains 2020 Hard
More PYQs from JEE Mains
- If \([x]\) denotes the greatest integer less than or equal to \(x\), then the value of the integral \(\int_{-\pi / 2}^{\pi / 2}[[x]-\sin x] d x\) is equal to:JEE Mains 2021 Hard
- A particle of mass \(20\,g\) is released with an initial velocity \(5\,m/s\) along the curve from the point \(A,\) as shown in the figure. The point \(A\) is at height \(h\) from point \(B.\) The particle slides along the frictionless surface. When the particle reaches point \(B,\) its angular momentum about \(O\) will be ......... \(kg - m^2/s\). [Take \(g = 10\,m/s^2\) ]
JEE Mains 2019 Medium - In the circuit shown, find \(C\) if the effective capacitance of the whole circuit is to be \(0.5\,\mu F.\) All values in the circuit are in \(\mu F.\)
JEE Mains 2019 Hard - A cricket ball of mass \(0.15\, kg\) is thrown vertically up by a bowling machine so that it rises to a maximum height of \(20 \;m\) after leaving the machine. If the part pushing the ball applies a constant force \(F\) on the ball and moves horizontally a distance of \(0.2\, m\) while launching the ball, the value of \(F(\) in \(N)\) is \(\left(g=10\, m s^{-2}\right)\)JEE Mains 2020 Medium
- Let \(\vec{a}, \vec{b}, \vec{c}\) be three non-coplanar vectors such that \(\overrightarrow{ a } \times \overrightarrow{ b }=4 \overrightarrow{ c }, \overrightarrow{ b } \times \overrightarrow{ c }=9 \overrightarrow{ a }\) and \(\overrightarrow{ c } \times \overrightarrow{ a }=\alpha \overrightarrow{ b }, \alpha>0\) . If \(|\vec{a}|+|\vec{b}|+|\vec{c}|=36\), then \(\alpha\) is equal to\(....\)JEE Mains 2022 Hard
- The velocity of a particle is \(v = v _{0}+ gt + Ft ^{2}\). Its position is \(x=0\) at \(t=0\); then its displacement after time \(( t =1)\) is :JEE Mains 2021 Easy