JEE Mains · Physics · STD 11 - 11. thermodynamics
In the reported figure, there is a cyclic process \(ABCDA\) on a sample of \(1\, {mol}\) of a diatomic gas. The temperature of the gas during the process \({A} \rightarrow {B}\) and \({C} \rightarrow {D}\) are \({T}_{1}\) and \({T}_{2}\left({T}_{1}\,>\,{T}_{2}\right)\) respectively. Choose the correct option out of the following for work done if processes \(B C\) and \(D A\) are adiabatic.
- A \({W}_{{AB}}\,<\,{W}_{{CD}}\)
- B \({W}_{{AD}}={W}_{{BC}}\)
- C \({W}_{{BC}}+{W}_{{DA}}\,>\,0\)
- D \({W}_{{AB}}={W}_{{DC}}\)
Answer & Solution
Correct Answer
(B) \({W}_{{AD}}={W}_{{BC}}\)
Step-by-step Solution
Detailed explanation
Work done in adiabatic process \(=\frac{-n R}{\gamma-1}\left(T_{f}-T_{i}\right)\) \(\therefore W _{ AD }=\frac{- nR }{\gamma-1}\left( T _{2}- T _{1}\right)\) \(\text { and } W _{ BC }=\frac{- nR }{\gamma-1}\left( T _{2}- T _{1}\right)\) \(\therefore W _{ AD }= W _{ BC }\)
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