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JEE Mains · Physics · STD 12 - 3. current electricity
In the given circuit diagram, the currents, \({I_1} = - \,0.3\,A,\,{I_4} = 0.8\,A\) and \({I_5} = 0.4\,A,\) are flowing as shown. The currents \(I_2,\,I_3\) and \(I_6,\) respectively are
- A \(1.1\,A,\,-\,0.4\,A,\,0.4\,A\)
- B \(1.1\,A,\,0.4\,A,\,0.4\,A\)
- C \(0.4\,A,\,1.1\,A,\,0.4\,A\)
- D \(-\,0.4\,A,\,0.4\,A,\,1.1\,A\)
Answer & Solution
Correct Answer
(B) \(1.1\,A,\,0.4\,A,\,0.4\,A\)
Step-by-step Solution
Detailed explanation
\(\mathrm{I}_{3}+\mathrm{I}_{5}=\mathrm{I}_{4} \quad \Rightarrow \quad \mathrm{I}_{3}=\mathrm{I}_{4}-\mathrm{I}_{5}=0.4\, \mathrm{A}\) \(\mathrm{I}_{1}+\mathrm{I}_{2}=\mathrm{I}_{4} \quad \Rightarrow \quad \mathrm{I}_{2}=\mathrm{I}_{4}-\mathrm{I}_{1}=1.1\, \mathrm{A}\)…
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