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JEE Mains · Physics · STD 12 - Current electricity
  • JEE Mains 2019
  • Medium
  • MCQ

In the given circuit diagram, the currents, \({I_1} =  - \,0.3\,A,\,{I_4} = 0.8\,A\) and \({I_5} = 0.4\,A,\) are flowing as shown. The currents \(I_2,\,I_3\) and \(I_6,\) respectively are

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Answer & Solution

Correct Answer

(B) \(1.1\,A,\,0.4\,A,\,0.4\,A\)

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\(\mathrm{I}_{3}+\mathrm{I}_{5}=\mathrm{I}_{4} \quad \Rightarrow \quad \mathrm{I}_{3}=\mathrm{I}_{4}-\mathrm{I}_{5}=0.4\, \mathrm{A}\)

\(\mathrm{I}_{1}+\mathrm{I}_{2}=\mathrm{I}_{4} \quad \Rightarrow \quad \mathrm{I}_{2}=\mathrm{I}_{4}-\mathrm{I}_{1}=1.1\, \mathrm{A}\)

\(\mathrm{I}_{3}+\mathrm{I}_{6}=\mathrm{I}_{2}+\mathrm{I}_{1} \Rightarrow \quad \mathrm{I}_{6}=\mathrm{I}_{2}+\mathrm{I}_{1}-\mathrm{I}_{3}=0.4 \,\mathrm{A}\)

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